How long will under-active thyroid keep me fat?

22 December 2008 - 02:00
By unknown

I am in my 40s and over the last year I have put on so much weight that I have had to buy clothes a size or two sizes bigger. I have not been overeating and have been eating as I have done since I was a teenager.

I am in my 40s and over the last year I have put on so much weight that I have had to buy clothes a size or two sizes bigger. I have not been overeating and have been eating as I have done since I was a teenager.

Two weeks ago I went to a doctor for a full medical, and blood tests. The blood results showed I have an under-active thyroid. My doctor prescribed a drug.

I don't expect the weight to suddenly fall off me, but do you know how long it will be until I get my old body back? I'm cutting back on carbs and sugar.

Too Big For My Liking, Sandton

Sister, as explained before, I have zero medical experience so I went to trusty Google to find out more for you.

According to Women24.com, the thyroid is a small gland situated around your windpipe, which "can have a devastating effect on energy levels and moods because it is responsible for producing hormones that influence almost all the metabolic processes in your body".

Apparently the most common thyroid problems involve abnormal production of thyroid hormones.

Too much of this hormone results in hyperthyroidism, caused by an over-active thyroid, which leads to restlessness, nervousness and weight loss.

Insufficient hormone production leads to hypothyroidism, caused by an under-active thyroid, which can result in a lack of energy, depression and weight gain.

A medical website reports that hypothyroidism is treated by taking a thyroxine replacement. It reports that it can take some time to get the dose right. Your doctor will adjust your dose according to the results of blood tests.

None of the sites I checked said how long it should or can take to lose weight and I presume it is slower than for people with a working thyroid. But persevere and you will see results.